9t^2-38.64t+35.2=0

Solution for 9t^2-38.64t+35.2=0 equation:

9t^2-38.64t+35.2=0

a = 9; b = -38.64; c = +35.2;
Δ = b2-4ac
Δ = -38.642-4·9·35.2
Δ = 225.8496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38.64)-\sqrt{225.8496}}{2*9}=\frac{38.64-\sqrt{225.8496}}{18}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38.64)+\sqrt{225.8496}}{2*9}=\frac{38.64+\sqrt{225.8496}}{18}
$